Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 9

Answer

$a=4$

Work Step by Step

The given equation is $\Rightarrow 4-\sqrt a=2$ Add $\sqrt a-2$ to each side. $\Rightarrow 4-\sqrt a+\sqrt a-2=2+\sqrt a-2$ Simplify. $\Rightarrow 2=\sqrt a$ Square each side of the equation. $\Rightarrow 2^2=(\sqrt{a})^2$ Simplify. $\Rightarrow 4=a$ Check $a=4$. $\Rightarrow 4-\sqrt a=2$ $\Rightarrow 4-\sqrt 4=2$ $\Rightarrow 4-\sqrt {2^2}=2$ $\Rightarrow 4-2=2$ $\Rightarrow 2=2$ True. Hence, the solution is $a=4$.
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