Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 8

Answer

$x=4$

Work Step by Step

The given equation is $\Rightarrow \sqrt x+6=8$ Subtract $6$ from each side. $\Rightarrow \sqrt x+6-6=8-6$ Simplify. $\Rightarrow \sqrt x=2$ Square each side of the equation. $\Rightarrow (\sqrt{x})^2=2^2$ Simplify. $\Rightarrow x=4$ Check $x=4$. $\Rightarrow \sqrt x+6=8$ $\Rightarrow \sqrt 4+6=8$ $\Rightarrow \sqrt {2^2}+6=8$ $\Rightarrow 2+6=8$ $\Rightarrow 8=8$ True. Hence, the solution is $x=4$.
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