Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 22

Answer

The surface area is $96\; in.^2$.

Work Step by Step

The given equation is $\Rightarrow s=\sqrt{\frac{A}{6}}$ Substitute edge length $s=4$. $\Rightarrow 4=\sqrt{\frac{A}{6}}$ Square each side of the equation. $\Rightarrow (4)^2=(\sqrt{\frac{A}{6}})^2$ Simplify. $\Rightarrow 16=\frac{A}{6}$ Multiply each side by $6$. $\Rightarrow 6\times 16=6\times \frac{A}{6}$ Simplify. $\Rightarrow 96=A$ Hence, the surface area is $96\; in.^2$.
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