Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 16

Answer

$y=6$

Work Step by Step

The given equation is $\Rightarrow 5\sqrt {y-2}=10$ Divide each side by $5$. $\Rightarrow \frac{5\sqrt {y-2}}{5}=\frac{10}{5}$ Simplify. $\Rightarrow \sqrt {y-2}=2$ Square each side of the equation. $\Rightarrow (\sqrt{y-2})^2=2^2$ Simplify. $\Rightarrow y-2=4$ Add $2$ fo each side. $\Rightarrow y-2+2=4+2$ Simplify. $\Rightarrow y=6$ Check $y=6$. $\Rightarrow 5\sqrt {y-2}=10$ $\Rightarrow 5\sqrt {6-2}=10$ $\Rightarrow 5\sqrt {4}=10$ $\Rightarrow 5\sqrt {2^2}=10$ $\Rightarrow 5(2)=10$ $\Rightarrow 10=10$ True. Hence, the solution is $y=6$.
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