Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 6

Answer

$p=36$

Work Step by Step

The given equation is $\Rightarrow \sqrt p-7=-1$ Add $7$ to each side. $\Rightarrow \sqrt p-7+7=-1+7$ Simplify. $\Rightarrow \sqrt p=6$ Square each side of the equation. $\Rightarrow (\sqrt{p})^2=6^2$ Simplify. $\Rightarrow p=36$ Check $p=36$. $\Rightarrow \sqrt p-7=-1$ $\Rightarrow \sqrt {36}-7=-1$ $\Rightarrow \sqrt {6^2}-7=-1$ $\Rightarrow 6-7=-1$ $\Rightarrow -1=-1$ True. Hence, the solution is $p=36$.
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