Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 14

Answer

$b=2$

Work Step by Step

The given equation is $\Rightarrow \sqrt {b+7}-5=-2$ Add $5$ to each side. $\Rightarrow \sqrt {b+7}-5+5=-2+5$ Simplify. $\Rightarrow \sqrt {b+7}=3$ Square each side of the equation. $\Rightarrow (\sqrt{b+7})^2=3^2$ Simplify. $\Rightarrow b+7=9$ Subtract $7$ from each side. $\Rightarrow b+7-7=9-7$ Simplify. $\Rightarrow b=2$ Check $b=2$. $\Rightarrow \sqrt {b+7}-5=-2$ $\Rightarrow \sqrt {2+7}-5=-2$ $\Rightarrow \sqrt {9}-5=-2$ $\Rightarrow \sqrt {3^2}-5=-2$ $\Rightarrow 3-5=-2$ $\Rightarrow -2=-2$ True. Hence, the solution is $b=2$.
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