Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 28

Answer

$y=3$

Work Step by Step

The given equation is $\Rightarrow \sqrt{y+1}=\sqrt{4y-8}$ Square each side of the equation. $\Rightarrow (\sqrt{y+1})^2=(\sqrt{4y-8})^2$ Simplify. $\Rightarrow y+1=4y-8$ Add $8-y$ to each side. $\Rightarrow y+1+8-y=4y-8+8-y$ Simplify. $\Rightarrow 9=3y$ Divide each side by $3$. $\Rightarrow \frac{9}{3}=\frac{3y}{3}$ Simplify. $\Rightarrow 3=y$ Check $y=3$. $\Rightarrow \sqrt{3+1}=\sqrt{4(3)-8}$ $\Rightarrow \sqrt{4}=\sqrt{12-8}$ $\Rightarrow \sqrt{4}=\sqrt{4}$ True. Hence, the solution is $y=3$.
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