Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 31

Answer

$p=12$ Check: $\sqrt {\frac{12}{2}-2}=\sqrt {12-8}$ $\sqrt 4=\sqrt 4$ which is correct.

Work Step by Step

$\sqrt {\frac{p}{2}-2}=\sqrt {p-8}$ Square each side of the equation to get $(\sqrt {\frac{p}{2}-2})^{2}=(\sqrt {p-8})^{2}$ $\implies \frac{p}{2}-2=p-8$ Simplifying, we have $-2+8=p-\frac{p}{2}$ Or $6=\frac{p}{2}$ $\implies p=6\times2=12$ Check: $\sqrt {\frac{12}{2}-2}=\sqrt {12-8}$ $\sqrt 4=\sqrt 4$ which is correct.
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