Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 20

Answer

The solution is $c=5$.

Work Step by Step

The given equation is $\Rightarrow 19-4\sqrt{3c-11}=11$ Subtract $19$ from each side. $\Rightarrow 19-4\sqrt{3c-11}-19=11-19$ Simplify. $\Rightarrow -4\sqrt{3c-11}=-8$ Divide each side by $-4$. $\Rightarrow \sqrt{3c-11}=2$ Square each side of the equation. $\Rightarrow (\sqrt{3c-11})^2=(2)^2$ Simplify. $\Rightarrow 3c-11=4$ Add $11$ to each side. $\Rightarrow 3c-11+11=4+11$ Simplify. $\Rightarrow 3c=15$ Divide each side by $3$. $\Rightarrow c=5$ Check $c=5$. $\Rightarrow 19-4\sqrt{3c-11}=11$ $\Rightarrow 19-4\sqrt{3(5)-11}=11$ $\Rightarrow 19-4\sqrt{15-11}=11$ $\Rightarrow 19-4\sqrt{4}=11$ $\Rightarrow 19-4(2)=11$ $\Rightarrow 19-8=11$ $\Rightarrow 11=11$ True. Hence, the solution is $c=5$.
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