Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 17

Answer

$r=7$

Work Step by Step

The given equation is $\Rightarrow -1=\sqrt {5r+1}-7$ Add $7$ to each side. $\Rightarrow -1+7=\sqrt {5r+1}-7+7$ Simplify. $\Rightarrow 6=\sqrt {5r+1}$ Square each side of the equation. $\Rightarrow 6^2=(\sqrt{5r+1})^2$ Simplify. $\Rightarrow 36=5r+1$ Subtract $1$ from each side. $\Rightarrow 36-1=5r+1-1$ Simplify. $\Rightarrow 35=5r$ Divide each side by $5$. $\Rightarrow \frac{35}{5}=\frac{5r}{5}$ Simplify. $\Rightarrow 7=r$ Check $r=7$. $\Rightarrow -1=\sqrt {5r+1}-7$ $\Rightarrow -1=\sqrt {5(7)+1}-7$ $\Rightarrow -1=\sqrt {35+1}-7$ $\Rightarrow -1=\sqrt {36}-7$ $\Rightarrow -1=\sqrt {6^2}-7$ $\Rightarrow -1=6-7$ $\Rightarrow -1=-1$ True. Hence, the solution is $r=7$.
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