Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 27

Answer

$x=9$

Work Step by Step

The given equation is $\Rightarrow \sqrt{2x-9}=\sqrt{x}$ Square each side of the equation. $\Rightarrow (\sqrt{2x-9})^2=(\sqrt{x})^2$ Simplify. $\Rightarrow 2x-9=x$ Add $9-x$ to each side. $\Rightarrow 2x-9+9-x=x+9-x$ Simplify. $\Rightarrow x=9$ Check $x=9$. $\Rightarrow \sqrt{2(9)-9}=\sqrt{9}$ $\Rightarrow \sqrt{18-9}=\sqrt{9}$ $\Rightarrow \sqrt{9}=\sqrt{9}$ True. Hence, the solution is $x=9$.
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