Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 13

Answer

$a=19$

Work Step by Step

The given equation is $\Rightarrow \sqrt {a-3}+5=9$ Subtract $5$ from each side. $\Rightarrow \sqrt {a-3}+5-5=9-5$ Simplify. $\Rightarrow \sqrt {a-3}=4$ Square each side of the equation. $\Rightarrow (\sqrt{a-3})^2=4^2$ Simplify. $\Rightarrow a-3=16$ Add $3$ to each side. $\Rightarrow a-3+3=16+3$ Simplify. $\Rightarrow a=19$ Check $a=19$. $\Rightarrow \sqrt {a-3}+5=9$ $\Rightarrow \sqrt {19-3}+5=9$ $\Rightarrow \sqrt {16}+5=9$ $\Rightarrow \sqrt {4^2}+5=9$ $\Rightarrow 4+5=9$ $\Rightarrow 9=9$ True. Hence, the solution is $a=19$.
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