Big Ideas Math - Algebra 1, A Common Core Curriculum

Published by Big Ideas Learning LLC
ISBN 10: 978-1-60840-838-2
ISBN 13: 978-1-60840-838-2

Chapter 10 - Radical Functions and Equations - 10.3 - Solving Radical Equations - Exercises - Page 564: 18

Answer

The solution is $s=10$.

Work Step by Step

The given equation is $\Rightarrow 2=\sqrt{4s-4}-4$ Add $4$ to each side. $\Rightarrow 2+4=\sqrt{4s-4}-4+4$ Simplify. $\Rightarrow 6=\sqrt{4s-4}$ Square each side of the equation. $\Rightarrow (6)^2=(\sqrt{4s-4})^2$ Simplify. $\Rightarrow 36=4s-4$ Add $4$ to each side. $\Rightarrow 36+4=4s-4+4$ Simplify. $\Rightarrow 40=4s$ Divide each side by $4$. $\Rightarrow 10=s$ Check $s=10$. $\Rightarrow 2=\sqrt{4s-4}-4$ $\Rightarrow 2=\sqrt{4(10)-4}-4$ $\Rightarrow 2=\sqrt{40-4}-4$ $\Rightarrow 2=\sqrt{36}-4$ $\Rightarrow 2=6-4$ $\Rightarrow 2=2$ True. Hence, the solution is $s=10$.
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