Answer
$3$ $MeV$
Work Step by Step
Total energy of the deuteron= kinetic energy of the deuteron+potential energy of the deuteron
$\implies E=K+U$
If the deuteron tunnels through the barrier, the value of $U=0 $ on the other side of the barrier because the the height of potential barrier is zero in this region.
Therefore, $K=E=3$ $MeV$
$\therefore$ The kinetic energy of the deuteron on the other side of the barrier is $3$ $MeV$
