Answer
The required weight of TNT is $~~1.18\times 10^8~N$
Work Step by Step
We can find the required number of moles:
$\frac{1.80\times 10^{14}~J}{3.40\times 10^6~J/mol} = 5.294\times 10^7~mol$
We can find the required mass:
$m = (5.294\times 10^7~mol)(0.227~kg/mol) = 1.202\times 10^7~kg$
We can find the weight:
$weight = mg = (1.202\times 10^7~kg)(9.8~m/s^2) = 1.18\times 10^8~N$
The required weight of TNT is $~~1.18\times 10^8~N$
