Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1148: 47

Answer

$1.01\times 10^7km $

Work Step by Step

We know that; $E=mc^2$ We plug in the known values to obtain: $E=320\times 10^{-6}Kg\times 3\times 10^8\frac{m}{s}=2.88\times 10^{13}J$ As $3.65\times 10^7J=1L$, then $\implies \frac{2.88\times 10^{13}}{3.65\times 10^7}=789041Liters $ We also know that 1 Liter=12.75km. Therefore; $\implies 189041\times12.75=1.01\times 10^7Km $
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