Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1148: 42

Answer

$E = 7.30~MeV$

Work Step by Step

We can find the change in mass: $\Delta M = M_f-M_i$ $\Delta M = (3)(4.001 51~u)-(11.996 71~u)$ $\Delta M = 0.00782~u$ $\Delta M = (0.00782)~(1.66\times 10^{-27}~kg)$ $\Delta M = 1.29812\times 10^{-29}~kg$ We can find the minimum required energy: $E = (1.29812\times 10^{-29}~kg)(3.0\times 10^8~m/s)^2$ $E = 11.68308\times 10^{-13}~J$ $E = (11.68308\times 10^{-13}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$ $E = 7.30~MeV$
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