Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1148: 44

Answer

$Q = 8.13~MeV$

Work Step by Step

We can find $Q$: $Q = (M_i-M_f)~c^2$ $Q = [(1.007825 u+18.998405 u)-(4.002603 u+15.994915 u)]~c^2$ $Q = (0.008712~u)~c^2$ $Q = (0.008712)~(1.66\times 10^{-27}~kg)~(3.0\times 10^8~m/s)^2$ $Q = 1.3015728\times 10^{-12}~J$ $Q = (1.3015728\times 10^{-12}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$ $Q = 8.13~MeV$
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