Answer
$K/E_o=0.41$
Work Step by Step
Relativistic kinetic energy is equal to $$K=(\gamma-1)mc^2$$ Also, relativistic energy is equal to $$E=mc^2$$ Therefore, $K/E_o$ is equal to $K/E_o=\frac{(\gamma-1)mc^2}{mc^2}=\gamma-1$.
Substituting $\gamma=1.41$ yields $K/E_o=1.41-1.00=0.41$.
