Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1148: 55b

Answer

$\gamma=1.41$

Work Step by Step

$\gamma$ is equal to $$\gamma=\frac{1}{\sqrt{1-\beta^2}}$$ Since $\beta=0.707$, $\gamma$ equals $$\gamma=\frac{1}{\sqrt{1-.707^2}}=1.41$$
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