Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1148: 50d

Answer

$\beta=0.1448$

Work Step by Step

We know that $\beta =\sqrt{1-\frac{1}{\gamma^2}}$ We plug in the known values to obtain: $\beta=\sqrt{1-\frac{1}{(1.011)^2}}=0.1448$
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