Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1148: 41a

Answer

$\gamma = 196.159$

Work Step by Step

We can express the energy in units of joules: $(100.000\times 10^6~eV)(\frac{1.6\times 10^{-19}~J}{1~eV}) = 1.6\times 10^{-11}~J$ We can find $\gamma$: $K = mc^2(\gamma-1)$ $\frac{K}{mc^2} = \gamma-1$ $\gamma = \frac{K}{mc^2}+1$ $\gamma = \frac{1.6\times 10^{-11}~J}{(9.109 381 88\times 10^{-31}~kg)(3.0\times 10^8~m/s)^2}+1$ $\gamma = 195.159+1$ $\gamma = 196.159$
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