Answer
$\gamma = 1.003$
Work Step by Step
We can find $\gamma$:
$K = mc^2~(\gamma-1) = 10.00~MeV$
$\gamma-1 = \frac{10.00~MeV}{mc^2}$
$\gamma = 1+\frac{10.00~MeV}{E_0}$
$\gamma = 1+\frac{10.00~MeV}{3727.40~MeV}$
$\gamma = 1.003$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 37 - Relativity - Problems - Page 1148: 50e
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
