Answer
$\gamma=20.57$
Work Step by Step
We know that:
$\gamma=\frac{K}{E_{0}}+1$
We plug in the known values to obtain:
$\gamma=\frac{10.00MeV}{0.5110MeV}+1=20.57$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 37 - Relativity - Problems - Page 1148: 50a
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