Answer
$F^-$ acts as a weak base in solution.
- $F^-(aq) + H_2O(l) \lt -- \gt HF(aq) + OH^-(aq)$
Work Step by Step
1. Protonate this anion, to get its conjugate acid:
$F^- --\gt HF$
2. Analyze the protonated compound.
- Weak acids have weak bases as conjugate pair.
- HF is a weak acid, therefore, $F^-$ acts as a weak base.
3. Now that we know that, write the equation where $F^-$ receives a proton from a water molecule, producing $OH^-$
- $F^-(aq) + H_2O(l) \lt -- \gt HF(aq) + OH^-(aq)$
