Answer
$ \frac{1}{3}log_5(x^2+1)-log_5(x+1)-log_5(x-1)$.
Work Step by Step
$log_5(\frac{\sqrt[3] {x^2+1}}{x^2-1})=log_5(\sqrt[3] {x^2+1})-log_5(x^2-1)=\frac{1}{3}log_5(x^2+1)-log_5(x+1)-log_5(x-1)$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 50
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