Answer
$1$
Work Step by Step
$\because \log_a M+\log_a N = \log_a (MN)$
$\therefore \log_8 2 + \log_8 4 = \log_8 (2 \cdot 4) = \log_8 8$
$\because \log_a a = 1$
$\therefore \log_8 8 = 1$
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