Answer
$ \log _{a}(M N)=\log _{a} M+\log _{a} N$
Work Step by Step
Recall the product rule for logarithms:
$$\log _{a}(AB)=\log _{a} A+\log _{a} B$$
Thus,
$$\log_a{MN}=\log_a{M}+\log_a{N}$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 5
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