Answer
$2$
Work Step by Step
$\because \log_a M+\log_a N = \log_a (MN)$
$\therefore \log_6 9 + \log_6 4 = \log_6 (9 \cdot 4) = \log_6 36$
With $36=6^2$,
$\log_6 36 = \log_6 6^2$
Since $\log_a a^r =r$, then,
$\log_6 6^2 = 2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 20
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