Answer
$1$
Work Step by Step
Recall:
$$\log_a{x}=y \longrightarrow a^y=x$$
Let $\quad \log _{a} a=y$
Then, using the definition above gives:
$$\log _{a}{a}=y\longrightarrow a^y=a\longrightarrow y=1$$
Hence,
$$\log_a{a}=y=1$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 2
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