Answer
$\ln{x}+x$
Work Step by Step
Recall:
$\log_a{(MN)} = \log_a{M}+\log_a{N}$
Using the rule above gives:
$\ln(x e^x) = \ln{x}+\ln{\left(e^x\right)}$
Recall also that $\ln{e^x} = x$
Thus,
$\ln{(x e^x)} = \boxed{\ln{x}+x}$