Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 44

Answer

$\ln{x}+x$

Work Step by Step

Recall: $\log_a{(MN)} = \log_a{M}+\log_a{N}$ Using the rule above gives: $\ln(x e^x) = \ln{x}+\ln{\left(e^x\right)}$ Recall also that $\ln{e^x} = x$ Thus, $\ln{(x e^x)} = \boxed{\ln{x}+x}$
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