Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 4 - Exponential and Logarithmic Functions - Section 4.5 Properties of Logarithms - 4.5 Assess Your Understanding - Page 331: 34

Answer

$3b$

Work Step by Step

With $27=3^3$, then $\ln27 = \ln(3^3)$ Recall that $\log_a \left(M^r\right) = r \log_a M$. Using the rule above gives: $\ln(3^3) = 3 \ln3$ With $\ln3 = b$, then $3 \ln3 = 3b$ Therefore, $\ln27 = \boxed{3b}$
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