Answer
(a) See graph.
(b) $-1\pm\sqrt 6$
(c) See graph.
Work Step by Step
(a) To obtain the graph of $y=-2(x+1)^2+12$ from $y=x^2$, shift the curve 1 unit to the left, stretch vertically by a factor of 2, reflect across the x-axis, then shift 12 units up. See graph.
(b) We can find the real zeros $x=-1\pm\sqrt 6$
(c) See graph.
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