Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 92

(a) See graph. (b) $-1\pm\sqrt 6$ (c) See graph.

(a) To obtain the graph of $y=-2(x+1)^2+12$ from $y=x^2$, shift the curve 1 unit to the left, stretch vertically by a factor of 2, reflect across the x-axis, then shift 12 units up. See graph. (b) We can find the real zeros $x=-1\pm\sqrt 6$ (c) See graph.