Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 52

Answer

$(0,3)$ and $(4,3)$

Work Step by Step

To find the points of intersection of $f(x)$ and $g(x)$, solve $f(x)=g(x)$ $$x^2-4x+3=3$$ $$x^2-4x=0$$ Taking $x$ as a common factor: $$x(x-4)=0$$ Use the Zero-Product Property by equating each factor to zero, then solve: \begin{align*} x =0 \hspace{10pt} &\text{ or } \hspace{10pt} x-4 =0\\ x =0 \hspace{10pt} &\text{ or } \hspace{10pt} x =4\\ \end{align*} To find the y-coordinates of the points of intersection, evaluate either of the two functions at $x=0$ and $x=4$ to obtain: $g(0)=3$ $g(4)=3$ Therefore, the points of intersection are $(0,3)$ and $(4,3)$
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