Answer
Zeros: $5\sqrt{2},-5 \sqrt{2}$
$x$-intercepts: $ 5\sqrt{2},-5 \sqrt{2}$
Work Step by Step
To find the zeros of a function $f$, solve the equation $f(x)=0$
The zeros of the function are also the $x-$intercepts.
Let $f(x)=0$:
$$x^2-50=0$$
Using the Square Root Method
$$x^2=50$$
$$ x = \pm \sqrt{50}$$
$\sqrt{50} = \sqrt{25 \times 2} = \sqrt{25} \times \sqrt{2} = 5 \sqrt{2}$
$$x=\pm 5\sqrt{2}$$
Thus, the zeros, which are also the $x$-intercepts, are $x = 5\sqrt{2},-5 \sqrt{2}$
