Answer
Zeros: $3 \sqrt{2}, -3 \sqrt{2}$
$x$-intercepts: $3 \sqrt{2}, -3 \sqrt{2}$
Work Step by Step
To find the zeros of a function $g$, solve the equation $g(x)=0$
The zeros of the function are also the $x-$intercepts.
Let $g(x)=0$:
$$x^2-18=0$$
Using the Square Root Method
$$x^2=18$$
$$ x = \pm \sqrt{18}$$
$\sqrt{18} = \sqrt{9 \times 2} = \sqrt{9} \times \sqrt{2} = 3 \sqrt{2}$
$$ x = \pm 3 \sqrt{2} $$
$\therefore x = 3\sqrt{2} \text{ or } x = -3 \sqrt{2}$
