Answer
Zeros: $2\sqrt{5},-2\sqrt{5}$
$x$-intercepts: $2\sqrt{5},-2\sqrt{5}$
Work Step by Step
To find the zeros of a function $f$, solve the equation $f(x)=0$
The zeros of the function are also the $x-$intercepts.
Let $f(x)=0$:
$$x^2-20=0$$
Using the Square Root Method
$$x^2=20$$
$$ x = \pm \sqrt{20}$$
$\sqrt{20} = \sqrt{4 \times 5} = \sqrt{4} \times \sqrt{5} = 2 \sqrt{5}$
$$x=\pm 2\sqrt{5}$$
Thus, the zeros, which are also the $x$-intercepts, are $ x = 2\sqrt{5},-2\sqrt{5}$
