Answer
the zeros are $x=6$ or $x=-2$ and the $x$-intercepts are $(6,0)$ and $(-2,0)$.
Work Step by Step
By factorization, we have
$$
g(x)=x(x-4)-12=x^2-4x-12=(x-6)(x+2)
.$$
That is, we have $x-6=0 $ or $x+2=0$. So the zeros are $x=6$ or $x=-2$ and the $x$-intercepts are $(6,0)$ and $(-2,0)$.