Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 28

Zeros: $-1,-3$ $x$-intercepts: $-1,-3$

To find the zeros of a function $g$, solve the equation $g(x)=0$ The zeros of the function are also the $x-$intercepts. Let $G(x)=0$: $$(x+2)^2-1=0$$ Using the Square Root Method $$(x+2)^2=1$$ $$ (x+2) = \pm \sqrt{1}$$ $$(x+2) = \pm 1$$ $\therefore x+2 = 1 \text{ or } x+2 = -1 $ $x+2 = 1 \to x = -1$ $x+2 = -1 \to x =-3$