Answer
the zeros are $x=-5$ or $x=5$ and the $x$-intercepts are $(-5,0)$ and $(5,0)$.
Work Step by Step
By factorization, we have
$$
H(x)=2x^2-50=2(x^2-25)=2(x+5)(x-5)
.$$
That is, we have $x+5=0 $ or $x-5=0$. So the zeros are $x=-5$ or $x=5$ and the $x$-intercepts are $(-5,0)$ and $(5,0)$.