Answer
Zeros: $\dfrac{3}{2}$
$x$-intercept: $\dfrac{3}{2}$
Work Step by Step
To find the zeros of a function $g$, solve the equation $g(x)=0$
The zeros of the function are also the $x-$intercepts.
Let $G(x)=0$:
$$4x^2+9-12x=0$$
Rearranging the Equation:
$$4x^2-12x+9$$
By Factoring:
$$(2x-3)(2x-3)=0$$
Use the Zero-Product Property by equating each unique factor to zero to obtain:
$2x-3 = 0$
$2x = 3$
$ x=\dfrac{3}{2}$
