Answer
the zeros are $x=-1/2$ or $x=3$ and the $x$-intercepts are $(-1/2,0)$ and $(3,0)$.
Work Step by Step
By factorization, we have
$$
g(x)=2x^2-5x-3=(2x+1)(x-3)
.$$
That is, we have $2x+1=0 $ or $x-3=0$. So the zeros are $x=-1/2$ or $x=3$ and the $x$-intercepts are $(-1/2,0)$ and $(3,0)$.