Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 16

the zeros are $x=-1$ or $x=-6$ and the $x$-intercepts are $(-1,0)$ and $(-6,0)$.

By factorization, we have $$ F(x)=x^2+7x+6=(x+1)(x+6) .$$ That is, we have $x+1=0 $ or $x+6=0$. So the zeros are $x=-1$ or $x=-6$ and the $x$-intercepts are $(-1,0)$ and $(-6,0)$.