Answer
the zeros are $x=2$ or $x=-3$ and the $x$-intercepts are $(2,0)$ and $(-3,0)$.
Work Step by Step
By factorization, we have
$$
F(x)=x^2+x-6=(x-2)(x+3)
.$$
That is, we have $x-2=0 $ or $x+3=0$. So the zeros are $x=2$ or $x=-3$ and the $x$-intercepts are $(2,0)$ and $(-3,0)$.