Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 15

Answer

the zeros are $x=2$ or $x=-3$ and the $x$-intercepts are $(2,0)$ and $(-3,0)$.

Work Step by Step

By factorization, we have $$ F(x)=x^2+x-6=(x-2)(x+3) .$$ That is, we have $x-2=0 $ or $x+3=0$. So the zeros are $x=2$ or $x=-3$ and the $x$-intercepts are $(2,0)$ and $(-3,0)$.
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