Chapter 2 - Linear and Quadratic Functions - Section 2.3 Quadratic Functions and Their Zeros - 2.3 Assess Your Understanding - Page 146: 78

Zero: $\dfrac{3}{2}$ $x$-intercept: $\dfrac{3}{2}$

To find the zeros of a function $f$, solve the equation $f(x)=0$ The zeros of the function are also the $x-$intercepts. Let $F(x)=0$: $$4x^2-12x+9=0$$ By Factoring $$(2x-3)^2=0$$ $$ 2x-3 =0$$ $$2x=3$$ $$x=\dfrac{3}{2}$$ Thus, the zero, which is also the $x$-intercept, is $\dfrac{3}{2}$