Answer
$ \frac{-2(x^2-5x-9)}{(x^2+9)^2}$
Work Step by Step
$\frac{(x^2+9)\cdot2-(2x-5)\cdot2x}{(x^2+9)^2}=\frac{2x^2+18-4x^2+10x}{(x^2+9)^2}=\frac{-2x^2+10x+18}{(x^2+9)^2}=\frac{-2(x^2-5x-9)}{(x^2+9)^2}$
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