Answer
$ \frac{(x+1)(x-1)}{(x^2+1)^2}$
Work Step by Step
$\frac{x\cdot2x-(x^2+1)\cdot1}{(x^2+1)^2}=\frac{2x^2-x^2-1}{(x^2+1)^2}=\frac{x^2-1}{(x^2+1)^2}=\frac{(x+1)(x-1)}{(x^2+1)^2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 87
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