Answer
$\frac{-4x-14}{(x-1)^2(x+2)^2}$
Work Step by Step
$\frac{2}{(x+2)^2(x-1)}-\frac{6}{(x+2)(x-1)^2}=\frac{2(x-1)-6(x+2)}{(x-1)^2(x+2)^2}=\frac{-4x-14}{(x-1)^2(x+2)^2}$
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