Answer
$ \frac{x}{(x+1)^2}$
Work Step by Step
$\frac{1-\frac{x}{x+1}}{2-\frac{x-1}{x}}=\frac{1-\frac{x}{x+1}}{2-\frac{x-1}{x}}\times\frac{x(x+1)}{x(x+1)}=\frac{x(x+1)-x^2}{2x(x+1)-(x^2-1)}=\frac{x}{x^2+2x+1}=\frac{x}{(x+1)^2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.6 Rational Expressions - A.6 Assess Your Understanding - Page A54: 76
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