Answer
$\frac{4x^2+1}{3x^2-1}$
Work Step by Step
$\frac{4+\frac{1}{x^2}}{3-\frac{1}{x^2}}=\frac{4+\frac{1}{x^2}}{3-\frac{1}{x^2}}\times\frac{x^2}{x^2}=\frac{4x^2+1}{3x^2-1}$
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